Question

Ayuda con resolución :
A) 5[(2x+1)-(3x+2)] › 2x-19

B) 8{2[(x-5)-2(x-3)]} ‹ 16

Answer 1

A) 5 (6X² +4X+3X+2) > 2X - 19 = 5 (6X² +7X+2) > 2X - 19= 30X² +35x + 10 > 2X - 19= 30X² + 35x + 10 -2x + 19 > 0 = 30X² + 33X +29=0 = x∈R

B) 8x(2(X-5+2X+6))x16 = 8(2(-X+1))x16 = 8(-2X+2)x16 = 128(-2X+2) = -256X+256