Question

Método de reducción 2x+3y=40 2x+y=20

Answer 1

2x+3y= 40. 2x+y=20

2x= 40-3y. 2x=20-y

X=(40-3y)/2. X=(20-y)/2

(40-3y)/2 = (20-y)/2

2(40-3y) = 2(20-y)

80-6y = 40-2y

80-40 =-2y+6y

40 = 4y

40/4 = Y

10 = Y

SUSTITUIMOS

2x + 3 (10) = 40

2x + 30 = 40

2x = 40 -30

2 x = 10

X = 10/2

X = 5

Respuestas : X = 5 Y = 10