Question

Me ayudarian a simplificar con proceso por favor

Answer 1

18.

$\frac{(8x-3)(4x^{2}+3x)^{\frac{1}{3}}}{3(4x^{2}-3x)^{\frac{2}{3}}} - \frac{(8x+3)(4x^{2}-3x)^{\frac{1}{3}}}{3(4x^{2}+3x)^{\frac{2}{3}}}\\\\\frac{(8x-3)(4x^{2}+3x)^{\frac{1}{3}}(4x^{2}+3x)^{\frac{2}{3}} - (8x+3)(4x^{2}-3x)^{\frac{1}{3}}(4x^{2}-3x)^{\frac{2}{3}}}{3(4x^{2}+3x)^{\frac{2}{3}}(4x^{2}-3x)^{\frac{2}{3}}}\\\\\frac{(8x-3)(4x^{2}+3x) - (8x+3)(4x^{2}-3x)}{3(16x^{4}-9x^{2})^{\frac{2}{3}}}$