Question

Alguien me puede ayudar con estas ecuaciones cuadráticas por favor:

(x-2)(3x-1)

(x+4)(2x+2)

3x²-27

x²-14x+49

5x²+3x

x²-2x+1

x²+3x-28

x²-81

5x²-25x

x²-36

3x²-5x+2

2x²-8x

Answer 1

(x-2)(3x-1)
x1 = 2
x2 = 1/3

(x+4)(2x+2)
x1 = -4
x2 = -2/2 = -1

3x²-27
3 (x^2-9)
3 (x +3)(x -3)
x1 = -3
x2 = 3

x²-14x+49
(x -7)(x-7)
x = 7

5x²+3x
x(5x+3)
x1 = 0
x2 = -3/5

x²-2x+1
(x-1)(x-1)
x= 1

x²+3x-28
(x +7) (x -4)
x1 = -7
x2 = 4

x²-81
(x +9 )(x-9)
x1 = -9
x2 = 9

5x²-25x
5x (x-5)
x1 = 0/5 = 0
x2 = 5

x²-36
(x +6)(x-6)
x1 = -6
x2 = 6

3x²-5x+2
((3x -3)(3x-2))/3*1
(x-1)(3x-2)
x1= 1
x2 = 2/3

2x²-8x
2x (x-4)
x1 = 0/2 = 0
x2 = 4