Question

PLOX AYUDA DOY 20 PUNTOS






5y - 21 = 51


5x+2 = 10




$x^{2}=4$





$y^{2}=21x2+7$

Answer 1

5y-21=51

5y=51+21

5y=72

y=72/5

y=14.4

5x+2=10

5x=10-2

5x=8

x=8/5

x²=4

x=√4

x=±2