Question

como puedo resolver x^2-4x=0 y 2x^2=x^2+x y x^2+4=5x+4?

Answer 1

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x²-4x=0

x . (x - 4) = 0

x=0 o x-4=0

x1=0 , x2=4

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2x² = x²+x

2x²-x²-x = 0

x²-x = 0

x . (x-1) = 0

x = 0 o x - 1 = 0

x1 = 0 , x2 =1

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x²+4=5x+4

x² = 5x

x² - 5x = 0

x . (x - 5) = 0

x = 0 o x - 5 = 0

x1 = 0 , x2 = 5