Question

Necesito ayuda resolviendo estas ecuaciones exponenciales, por favor:

Answer 1

Aplicando propiedades operacionales de logaritmos

g. xlog7 = log2          

x = log2/log7    log2 = 0.3010      log7 = 0.8451

x = (0.3010)/(0.8451) = 0.3562

h. (x + 1)log5 = log6

x + 1 = log6/log5        x = log6/log5 - 1        log6 = 0.7782      log5 = 0.6990

x = (0.7782)/(0.6990) - 1 = 0.1133

e. (2x - 1)log3 = log112

2x - 1 = log112/log3         2x = log11/log3 + 1       x = (log112/log3 + 1)/2

log112 = 2.0492     log3 = 0.4771

x = [(2.0492)/(0.4771) + 1]/2 = 2.6476

f. 6^(- x +1 - x + 2 - x + 3 - x) = 259

6^(- 4x + 6) = 259

(- 4x + 6)log6 = log259       - 4x + 6 = log259/log6      6 - log259/log6 = 4x

x = (6 - log259/log6)/4             log259 = 2.4133       log6 = 0.7782

x = [6 - (2.4133)/(0.7782)]/4 = 0.7247