Question

Por FAVOR. Demostrar que:
Tg A + Ctg A = Sec A×Cos A

Answer 1

Hola,

$\tan(A) + \cot(A) = \sec(A) \times \csc(A)$

Demostrar la Identidad Trigonométrica:

$\tan(A) + \cot(A) = \sec(A) \times \csc(A) \\ \frac{ \sin(A) }{ \cos(A) } + \frac{ \cos(A) }{ \sin(A) } = \sec(A) \times \csc(A) \\ \frac{ \sin {}^{2} (A) + \cos {}^{2} (A) }{ \cos(A) \times \sin(A) } = \sec(A) \times \csc(A)\\ \frac{1}{ \cos(A) \times \sin(A) } = \sec(A) \times \csc(A) \\ \frac{1}{ \cos(A) } \times \frac{1}{ \sin(A) } = \sec(A) \times \csc(A) \\ \sec(A) \times \csc(A) = \sec(A) \times \csc(A)$



Espero que te sirva, Saludos.