Question

Con procedimiento porfavor
Ecuaciones:formula general
5x' 2-7x-90=0

Answer 1

la ecuacion esta mal ecrita, escribela bien y te digo

Answer 2

x'2 imagino que quisiste poner X^2 entonces:
${5x}^{2} - 7x - 90 = 0$
Desarrollo:
$5 {x}^{2} - 7x - 90 = 0 \\ \\5(x {}^{2} - \frac{7}{5} x - 18) = 0 \\ \\ {x}^{2} - \frac{7}{5} x - 18 = 0 \\ \\ (x - \frac{7}{10} {)}^{2} - \frac{49}{100} - 18 = 0 \\ \\ ( {x - \frac{7}{10} )}^{2} - \frac{1849}{100} = 0 \\ \\ {(x - \frac{7}{10}) }^{2} = \frac{1849}{100} \\ \\ \sqrt{( {x - \frac{7}{10} }^{2}) } = \sqrt{ \frac{1849}{100} } \\ \\ |x - \frac{7}{10} | = \frac{43}{10} \\ \\ entonces \\ x = \frac{43}{10} + \frac{7}{10} = \frac{50}{10} = 5 \\ \\ o \\ \\ x = - \frac{43}{10} + \frac{7}{10} = \frac{ - 36}{10} = \frac{ - 18}{5}$
solución: {-18/5; 5}