Question

hola xfis ayúdenme a factorizar esto
es el caso 7
12m²-13m-35.
gracias yo lo intente y no me sale

Answer 1

$12m^2-13m-35 =0 \\ \\ m_{1y2}= \frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ m_{1y2}= \frac{13\pm \sqrt{169-(4*12*(-35))}}{2*(12)} \\ \\ m_{1y2}= \frac{13\pm \sqrt{169+1680}}{24} \\ \\ m_{1y2}= \frac{13\pm \sqrt{1849}}{24} \\ \\ m_{1y2}= \frac{13\pm43}{24} \\ \\ m_{1}= \frac{13\pm43}{24}\to m_ 1= \frac{56}{24} \to m_1= \frac{7}{3} \\ \\ m_{2}= \frac{13\pm43}{24}\to m_ 2= \frac{-30}{24} \to m_2=- \frac{5}{4}$

$12m^2-13m-35 =(m- \frac{7}{3})(m+ \frac{5}{4})$

Espero que te sirva, salu2!!!!