Question

Halle el valor de “y”, si: log2 (x -3) = 3 y log y (3x -1) = 5

Answer 1

log2 (x -3) = 3

2³ = x - 3

8 = x -3

x = 11

log y (3x -1) = 5

y⁵ = 3x -1

como x = 11 reemplazamos

y⁵ = 3(11) - 1

y⁵ = 32

y⁵ = 2⁵

y = 2