Question

Cual es la fórmula molecular de 49.02 c 2.743 de h 48.24de CL si su masa.molecular es. De 147.0

Answer 1

Cual es la fórmula molecular de 49.02 C, 2.743 de H, 48.24 de Cl si su masa.molecular es de 147.0

1. calcular moles

C: 49.02 g/ 12 g/mol = 4.085 mol

H: 2.743 g / 1 = 2.743 mol

Cl: 48.24 g/ 35.45 g/mol = 1.3607 mol

2. dividir entre el menor de los resultados

C: 4.085 mol / 1.3607 mol = 3

H:  2.743 mol / 1.3607 mol = 2

Cl: 1.3607 mol / 1.3607 mol = 1

3. FE: C3H2Cl

4. calcular Mm de la FE

C: 3 x 12 = 36 g/mol

H: 2 x 1 = 2 g/mol

Cl: 1 x 35.45 = 35.45 g/mol

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         Mm = 73.45 gmol

5. calcular n

n = Mm FM / Mm FE

n = 147 g/mol / 73.45 g/mol

n = 2

6. FM: (C3H2Cl)2 = C6H4Cl2