Question

AYUDAAAA POR FAVOR:

Resuelve:

Answer 1

Resuelve:

$\frac{7}{24}-\frac{\frac{13}{15}}{\frac{2x}{3}+\frac{4}{5}}=\frac{1}{4}$

$\frac{7}{24}\cdot \:24\left(\frac{2x}{3}+\frac{4}{5}\right)-\frac{\frac{13}{15}}{\frac{2x}{3}+\frac{4}{5}}\cdot \:24\left(\frac{2x}{3}+\frac{4}{5}\right)=\frac{1}{4}\cdot \:24\left(\frac{2x}{3}+\frac{4}{5}\right)$

$7\left(\frac{2x}{3}+\frac{4}{5}\right)-\frac{104}{5}=6\left(\frac{2x}{3}+\frac{4}{5}\right)$

$7\left(\frac{2x}{3}+\frac{4}{5}\right)-\frac{104}{5}+\frac{104}{5}=6\left(\frac{2x}{3}+\frac{4}{5}\right)+\frac{104}{5}$

$7\left(\frac{2x}{3}+\frac{4}{5}\right)=4x+\frac{128}{5}$

$7\left(\frac{2x}{3}+\frac{4}{5}\right)-4x=4x+\frac{128}{5}-4x$

$\frac{28}{5}+\frac{2x}{3}=\frac{128}{5}$

$\frac{28}{5}+\frac{2x}{3}-\frac{28}{5}=\frac{128}{5}-\frac{28}{5}$

$\frac{2x}{3}=20$

$\frac{3\cdot \:2x}{3}=20\cdot \:3$

$2x=60$

$\frac{2x}{2}=\frac{60}{2}$

$x=30$

¡Espero haberte ayudado Baba21!