Question

sen x = 1 - cos^2x / 1+senx

Answer 1

Sen x = 1 - cos^2x / 1+senx cos²x + sen²x=1 ⇒ cos²x= 1- sen²x

Sen x = 1 - (1 - sen²x) / 1+senx

sen x = 1 - (1 - senx)*(1 + senx)/ 1 + senx

sen x = 1 - (1 - senx)

sen x = 1 - 1 + sen x

sen x = sen x