Question

calcula la densidad del hierro si 393 g ocupan un volumen de 50 ml

Answer 1

Datos:

${\displaystyle \rho=?$

m=393grs

V=50ml= 50cm^{3}

${\displaystyle \rho ={\frac {m}{V}}\,}$

${\displaystyle \rho ={\frac {393grs}{50cm^{3}}}\,}$

${\displaystyle \rho=7,86 grs/cm^{3}$