Question

[(3/7)^2)]^3=
[(1/3)^2]^3×(1/3)^2=
(4/3^3)+(4/3)^2=

Answer 1

Siempre tienes que operar primero lo que esta dentro de paréntesis

[(3/7)^2)]^3= [9/49]^3= (9*9*9)/(49*49*49)= 729/117,649= 0.0061 //

[(1/3)^2]^3×(1/3)^2= [1/9]^3 * (1/9)= 1/729 + 1/9 = 1/6,561 //

(4/3^3)+(4/3)^2= 69/27+16/9 = 1053/243 = 4.33