Question

halle la ecuacion cuadratica cuyas raices son
$x _{1} = 2 \: y \: x _{2} = \frac{1}{3}$

Answer 1

$x_{1}=2\\ \\ x_{2}=\frac{1}{3} \\ \\ (x-2)(x-\frac{1}{3} )=x^{2} -\frac{x}{3}-2x+\frac{2}{3}\\\\=x^{2} -\frac{7}{3}x+\frac{2}{3}$