Question

dados los polinomios:
calcular:

P(x)-U(x) =
P(x)+R(x)=
S(x)+T(x)+U(x)=
P(x)+2Q(x)-R(x)
Q(x)+R(x)-P(x)

Answer 1

P(x)-U(x)= (4x^2-1)-(x^2+2) =4x^2-1-x^2-2 =3x^2-3

P(x)+R(x)=(4x^2-1)+(6x^2+x+1)= 4x^2-1+6x^2+x+1= 10x^2+x

S(x)+T(x)+U(x)=(1/2x^2+4)+(3/2x^2+5)+(2x^2+2) = 1/2x^2+4+3/2x^2+5+2x^2+2 = 4x^2+11

P(x)+2Q(x)-R(x)= (4x^2-1)+(2(1/2x^2+4))-(6x^2+x+1)= 4x^2-1+x^2+8-6x^2-x-1= -x^2-x+6

Q(x)+R(x)-P(x)= (1/2x^2+4)+(6x^2+x+1)-(4x^2-1)= 1/2x^2+4+6x^2+x+1-4x^2+1=\frac{1}{4x^2+x+6}

Answer 2

Respuesta:

P(x)-U(x)= (4x^2-1)-(x^2+2) =4x^2-1-x^2-2 =3x^2-3

P(x)+R(x)=(4x^2-1)+(6x^2+x+1)= 4x^2-1+6x^2+x+1= 10x^2+x

S(x)+T(x)+U(x)=(1/2x^2+4)+(3/2x^2+5)+(2x^2+2) = 1/2x^2+4+3/2x^2+5+2x^2+2 = 4x^2+11

P(x)+2Q(x)-R(x)= (4x^2-1)+(2(1/2x^2+4))-(6x^2+x+1)= 4x^2-1+x^2+8-6x^2-x-1= -x^2-x+6

Q(x)+R(x)-P(x)= (1/2x^2+4)+(6x^2+x+1)-(4x^2-1)= 1/2x^2+4+6x^2+x+1-4x^2+1=\frac{1}{4x^2+x+6}

Explicación paso a paso:

WTF