AYUDAAA :(
hay que unir cada binomio al cubo con los coeficientes de su desarrollo

Adjuntos:

Respuestas

Respuesta dada por: enriqueakatsuki
18

 23)\\ (2a+3b)^{3}=8a^{3}+3(2a)^{2}(3b)+3(2a)(3b)^{2}+27b^{3}   \\=8a^{3}+36a^{2}b+54ab^{2}+27b^{3} =8,36,54,27-------(c)\\       \\ 24)\\ (5m^{2}+1)^{3}=125m^{6}+3(25m^{4})+3(5m^{2})+1\\      =125m^{6}+75m^{4} +15m^{2}+1=125,75,15,1  --------(e)\\\\ 25) \\ (1-2x^{2} )^{3}=1-3(2x^{2} )+3(4x^{4})-8x^{6}   \\ 1-6x^{2} +12x^{4}-8x^{6}=1,-6,12,-8------(d)


 26)\\\\ (3y^{2} -4x)^{3}  =27y^{6}-3(3y^{2})^{2}(4x)+3(3y^{2})(4x)^{2}-64x^{3}\\       =27y^{6}-108y^{2}x+144y^{2} x-64x^{3}=27,-108,144,-64------(f)\\    \\ 27)\\ \\ (4x-1)^{3}=64x^{3}-3(16x^{2}   )+3(4x)-1\\ 64x^{3}-48x^{2}  +12x-1=64,-48,12,-1-----(a)\\ \\ 28)\\ \\ (3w+5)^{3}=27w^{3}+3(9w^{2})(5)+3(3w)(25)+125\\    27w^{3}+135w^{2}+225w+125=27,135,225,125-----(b)\\   \\ Saludos

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