Question

Por favor me ayudan a resolver esto: x^2- {-3x + [ x ( x+1 ) + 4 ( x^2-1)-4 x^2] }= 0

Answer 1

${x}^{2} - ( - 3x + (x(x + 1) + 4( {x}^{2} - 1) - 4 {x}^{2} )) = 0$
x²-(x²+x+4x²-4-4x²)=0
x²-x²-x+4=0
-x+4=0
-x=0-4
-x=-4
4=x