Question

cuantos moles de NH3 se producen cuando un exceso de N2 reaccióna con 2.00g de H2. N2 +H2 => NH3

Answer 1

N2 + 3 H2 → 2 NH3

Mm NH3 = 17 g/mol

N2 = 28 g/mol

calcular moles de NH3

n NH3 = 2.00 g N2 x 1 mol N2 x 2 mol NH3

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28 g N2 1 mol N2

n NH3 = 0.142 moles